Solving Exponential and Logarithmic Equations

Exponential Equations

The variable is in the exponent:

2x=83x=20ex=52^x = 8 \qquad 3^x = 20 \qquad e^x = 5


Easy Case: Same Base

If both sides have the same base, match the exponents.


Example: Solve 2x=82^x = 8

Rewrite 8 as a power of 2:

2x=232^x = 2^3

Same base, so exponents are equal:

x=3x = 3


Example: Solve 32x=813^{2x} = 81

Rewrite 81 as a power of 3:

32x=343^{2x} = 3^4

Match exponents:

2x=4⇒x=22x = 4 \quad \Rightarrow \quad x = 2


Hard Case: Use Logarithms

When you can’t match bases, take the log of both sides.

Key property: log⁡(an)=n⋅log⁡(a)\log(a^n) = n \cdot \log(a)


Example: Solve 2x=102^x = 10

Can’t write 10 as a power of 2. Take log of both sides:

log⁡(2x)=log⁡(10)x⋅log⁡(2)=1x=1log⁡(2)x≈3.32\begin{aligned} \log(2^x) &= \log(10) \\ x \cdot \log(2) &= 1 \\ x &= \frac{1}{\log(2)} \\ x &\approx 3.32 \end{aligned}

Example: Solve ex=7e^x = 7

Take ln of both sides (natural log pairs with base ee):

ln⁡(ex)=ln⁡(7)x=ln⁡(7)x≈1.95\begin{aligned} \ln(e^x) &= \ln(7) \\ x &= \ln(7) \\ x &\approx 1.95 \end{aligned}

Example: Solve 5x+1=305^{x+1} = 30

log⁡(5x+1)=log⁡(30)(x+1)⋅log⁡(5)=log⁡(30)x+1=log⁡(30)log⁡(5)x=log⁡(30)log⁡(5)−1x≈1.11\begin{aligned} \log(5^{x+1}) &= \log(30) \\ (x+1) \cdot \log(5) &= \log(30) \\ x + 1 &= \frac{\log(30)}{\log(5)} \\ x &= \frac{\log(30)}{\log(5)} - 1 \\ x &\approx 1.11 \end{aligned}

Logarithmic Equations

The variable is inside the log:

log⁡(x)=2ln⁡(x+1)=3\log(x) = 2 \qquad \ln(x + 1) = 3

Strategy: Convert to exponential form.


Example: Solve log⁡(x)=2\log(x) = 2

Convert to exponential form:

102=x10^2 = x

x=100x = 100


Example: Solve ln⁡(x)=4\ln(x) = 4

Convert to exponential form:

e4=xe^4 = x

x≈54.6x \approx 54.6


Example: Solve log⁡2(x−1)=5\log_2(x - 1) = 5

Convert to exponential form:

25=x−132=x−1x=33\begin{aligned} 2^5 &= x - 1 \\ 32 &= x - 1 \\ x &= 33 \end{aligned}

Summary

Equation typeStrategy
bx=byb^x = b^yMatch exponents: x=yx = y
bx=cb^x = cTake log: x=log⁡(c)log⁡(b)x = \dfrac{\log(c)}{\log(b)}
log⁡b(x)=c\log_b(x) = cConvert to exponential: x=bcx = b^c