Logarithm Properties

The Three Main Properties

These come directly from exponent laws.


Product Rule

log⁡b(xy)=log⁡b(x)+log⁡b(y)\log_b(xy) = \log_b(x) + \log_b(y)

Log of a product = sum of the logs.


Why it works:

If bm=xb^m = x and bn=yb^n = y, then:

xy=bm⋅bn=bm+nxy = b^m \cdot b^n = b^{m+n}

So log⁡b(xy)=m+n=log⁡b(x)+log⁡b(y)\log_b(xy) = m + n = \log_b(x) + \log_b(y).


Example:

log⁡(6)=log⁡(2×3)=log⁡(2)+log⁡(3)\log(6) = \log(2 \times 3) = \log(2) + \log(3)


Quotient Rule

log⁡b(xy)=log⁡b(x)−log⁡b(y)\log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y)

Log of a quotient = difference of the logs.


Why it works:

If bm=xb^m = x and bn=yb^n = y, then:

xy=bmbn=bm−n\frac{x}{y} = \frac{b^m}{b^n} = b^{m-n}

So log⁡b(xy)=m−n=log⁡b(x)−log⁡b(y)\log_b\left(\frac{x}{y}\right) = m - n = \log_b(x) - \log_b(y).


Example:

log⁡(5)=log⁡(102)=log⁡(10)−log⁡(2)=1−log⁡(2)\begin{aligned} \log(5) &= \log\left(\frac{10}{2}\right) \\ &= \log(10) - \log(2) \\ &= 1 - \log(2) \end{aligned}

Power Rule

log⁡b(xn)=n⋅log⁡b(x)\log_b(x^n) = n \cdot \log_b(x)

Log of a power = exponent times the log.


Why it works:

If bm=xb^m = x, then m=log⁡b(x)m = \log_b(x), and:

xn=(bm)n=bmn\begin{aligned} x^n &= (b^m)^n \\ &= b^{mn} \end{aligned}

So log⁡b(xn)=mn\log_b(x^n) = mn.

Substitute m=log⁡b(x)m = \log_b(x):

log⁡b(xn)=n⋅log⁡b(x)\log_b(x^n) = n \cdot \log_b(x)


Example:

log⁡(8)=log⁡(23)=3⋅log⁡(2)\log(8) = \log(2^3) = 3 \cdot \log(2)


Summary

PropertyRule
Productlog⁡b(xy)=log⁡b(x)+log⁡b(y)\log_b(xy) = \log_b(x) + \log_b(y)
Quotientlog⁡b(xy)=log⁡b(x)−log⁡b(y)\log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y)
Powerlog⁡b(xn)=n⋅log⁡b(x)\log_b(x^n) = n \cdot \log_b(x)

Special Values

log⁡b(1)=0\log_b(1) = 0

Because b0=1b^0 = 1.

log⁡b(b)=1\log_b(b) = 1

Because b1=bb^1 = b.


Change of Base Formula

To convert between bases:

log⁡b(x)=log⁡a(x)log⁡a(b)\log_b(x) = \frac{\log_a(x)}{\log_a(b)}

Most useful form:

log⁡b(x)=log⁡(x)log⁡(b)=ln⁡(x)ln⁡(b)\log_b(x) = \frac{\log(x)}{\log(b)} = \frac{\ln(x)}{\ln(b)}


Example: Calculate log⁡2(10)\log_2(10)

log⁡2(10)=log⁡(10)log⁡(2)=10.301≈3.32\begin{aligned} \log_2(10) &= \frac{\log(10)}{\log(2)} \\[0.5em] &= \frac{1}{0.301} \\[0.5em] &\approx 3.32 \end{aligned}