Nothing New to Memorize
The double angle formulas are not a fresh set of rules. They are the addition formulas with both angles the same.
Set B=A in sin(A+B) and you get sin(A+A)=sin2A. That is all a “double angle” is.
The yellow ray turns at angle θ. The green ray turns at 2θ, sweeping twice as fast. The two bars show sin2θ and 2sinθcosθ locked together, equal at every instant. That equality is the formula.
Deriving Sine
Start from the addition formula and let the two angles be equal:
sin2θ=sin(θ+θ)=sinθcosθ+cosθsinθ=2sinθcosθ sin2θ=2sinθcosθ
Deriving Cosine
Same move with the cosine addition formula:
cos2θ=cos(θ+θ)=cosθcosθ−sinθsinθ=cos2θ−sin2θ cos2θ=cos2θ−sin2θ
Cosine Has Three Faces
This is where cosine gets useful. Using the Pythagorean identity cos2θ+sin2θ=1, we can rewrite cos2θ in two more ways.
Replace cos2θ with 1−sin2θ:
cos2θ=(1−sin2θ)−sin2θ=1−2sin2θ
Replace sin2θ with 1−cos2θ:
cos2θ=cos2θ−(1−cos2θ)=2cos2θ−1
So all three of these are the same thing:
| Form | Use it when |
|---|
| cos2θ−sin2θ | you know both |
| 1−2sin2θ | you only know sinθ |
| 2cos2θ−1 | you only know cosθ |
Pick the version that matches what you already have.
Tangent
Setting B=A in the tangent formula gives:
tan2θ=1−tan2θ2tanθ
Don’t Fall for the Shortcut
Doubling the angle is not doubling the sine:
sin2θ=2sinθ
The green bar in the animation is sin2θ, but the true value is 2sinθcosθ. That extra cosθ factor is the whole point.
Example
Suppose sinθ=53 and θ is acute. Find sin2θ.
First get cosθ from the Pythagorean identity: cosθ=54.
Then:
sin2θ=2sinθcosθ=2⋅53⋅54=2524
The Set to Know
| Formula | Result |
|---|
| sin2θ | 2sinθcosθ |
| cos2θ | cos2θ−sin2θ=1−2sin2θ=2cos2θ−1 |
| tan2θ | 1−tan2θ2tanθ |