Direct Proof

What is a Direct Proof?

The simplest kind of proof. You want to prove:

PQP \to Q

“If P, then Q.”


The Method

  1. Assume P is true
  2. Use logic to show Q must follow
  3. Done

Start at P. Take logical steps. Arrive at Q.


Example 1: Even Squares

Claim: If nn is even, then n2n^2 is even.


Proof:

  • Assume nn is even
  • By definition, n=2kn = 2k for some integer kk
n2=(2k)2=4k2=2(2k2)\begin{aligned} n^2 &= (2k)^2 \\ &= 4k^2 \\ &= 2(2k^2) \end{aligned}
  • This is 2×(something)2 \times (\text{something}), so n2n^2 is even

We assumed even, we got even. Done.


Example 2: Sum of Odds

Claim: The sum of two odd numbers is even.


Proof:

  • Assume aa and bb are both odd
  • By definition:
    • a=2m+1a = 2m + 1 for some integer mm
    • b=2n+1b = 2n + 1 for some integer nn

Add them together:

a+b=(2m+1)+(2n+1)=2m+2n+2=2(m+n+1)\begin{aligned} a + b &= (2m + 1) + (2n + 1) \\ &= 2m + 2n + 2 \\ &= 2(m + n + 1) \end{aligned}
  • This is 2×(something)2 \times (\text{something}), so the sum is even

Two odds always make an even.


Example 3: Consecutive Product

Claim: If nn is an integer, then n(n+1)n(n+1) is even.


Proof:

  • Assume nn is an integer
  • Either nn is even or nn is odd

Case 1: nn is even

  • n(n+1)=even×anything=evenn(n+1) = \text{even} \times \text{anything} = \text{even}

Case 2: nn is odd

  • Then n+1n+1 is even

  • n(n+1)=anything×even=evenn(n+1) = \text{anything} \times \text{even} = \text{even}

  • Either way, the product is even

Consecutive integers — one is always even.


The Pattern

Direct proofs often rely on definitions.

TermDefinition
Evenn=2kn = 2k for some integer kk
Oddn=2k+1n = 2k + 1 for some integer kk
Divisible by 3n=3kn = 3k for some integer kk

Plug in the definition, do the algebra, show what you need.

Definition in, result out.